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</o:shapelayout></xml><![endif]--></head><body lang=EN-CA link=blue vlink=purple><div class=WordSection1><p class=MsoPlainText>Dear Ron<o:p></o:p></p><p class=MsoPlainText><o:p> </o:p></p><p class=MsoPlainText>>Legal limit from 2008: 2000 mg/m3; from 2015: 1250 mg/m3<o:p></o:p></p><p class=MsoPlainText><span style='color:black'><o:p> </o:p></span></p><p class=MsoPlainText><span style='color:black'>I think that is 2000/1.24 = 1613 ppm. Unless that is an undiluted value, it is pretty high. 1250/1.24 (or 1.25) = 1000 ppm which is in my 'very good' category of burner. It represents a CO/CO<sub>2</sub> ratio of about 0.3%.<o:p></o:p></span></p><p class=MsoPlainText><span style='color:black'><o:p> </o:p></span></p><p class=MsoPlainText><span style='color:black'>Because there is a fixed CO<sub>2</sub> Max value for any fuel, one can actually use the CO(EF) value to determine the CO/CO<sub>2</sub> ratio. It is actually more accurate that trying to measure using a calculated CO<sub>2</sub> value. If some <i>must</i> know how to do it, I will write it out. I once wrote it out for Tami so I can try to find that doc.<o:p></o:p></span></p><p class=MsoPlainText><span style='color:black'><o:p> </o:p></span></p><p class=MsoPlainText><span style='color:black'>The Testo gas combustion analyser calculates the CO<sub>2</sub> Max automatically when you enter the dry, ash-free fuel composition. It is the theoretical CO<sub>2</sub> value with perfect combustion and no dilution (0% O<sub>2</sub>). As the CO is subtracting carbon from the CO<sub>2</sub>, the having the CO(EF) value (0% O<sub>2</sub>) you can make a comparison based on [CO/(CO<sub>2</sub>/CO/2)].<o:p></o:p></span></p><p class=MsoPlainText><span style='color:black'><o:p> </o:p></span></p><p class=MsoPlainText><span style='color:black'>Regards<o:p></o:p></span></p><p class=MsoPlainText><span style='color:black'>Crispin<o:p></o:p></span></p><p class=MsoPlainText><span style='color:black'><o:p> </o:p></span></p></div></body></html>