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</o:shapelayout></xml><![endif]--></head><body bgcolor=white lang=EN-CA link="#0563C1" vlink="#954F72"><div class=WordSection1><p class=MsoNormal><span style='color:#1F497D'>Dear Lanny<o:p></o:p></span></p><p class=MsoNormal><span style='color:#1F497D'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:#1F497D'>It is not really the latent of evaporation that is relevant (though the number is the same). It is the latent heat of condensation that is generally agreed is not realisable as useful energy for cooking purposes.<o:p></o:p></span></p><p class=MsoNormal><span style='color:#1F497D'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:#1F497D'>There is a 60 kJ error in it conceptually, however. It does not include as unrealisable the energy released by cooling the condensed water to 20 C. That is why Baldwin and I agree it (the estimated deduction from HHV if the H2 content is not known) should be 1.38 not 1.32 but, who’s listening?<o:p></o:p></span></p><p class=MsoNormal><span style='color:#1F497D'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:#1F497D'>It is an bit arbitrary and that is what is used.  <o:p></o:p></span></p><p class=MsoNormal><span style='color:#1F497D'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:#1F497D'>Regards<o:p></o:p></span></p><p class=MsoNormal><span style='color:#1F497D'>Crispin<o:p></o:p></span></p><p class=MsoNormal><span style='color:#1F497D'><o:p> </o:p></span></p><p class=MsoNormal><o:p> </o:p></p><div><p class=MsoNormal><span style='font-size:13.5pt'>If the reaction takes place in a gaseous state, why does the laden heat of evaporation apply?</span><span style='font-size:12.0pt;mso-fareast-language:EN-CA'><o:p></o:p></span></p></div></div></body></html>