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Frans,<br>
<br>
Thanks.<br>
<br>
I really like the numbers that 1 kg of wood contains (or can
yield) 4 KWh. That is a very useful figure.<br>
<br>
One revision of your other comments. <br>
Pyrolysis releases about 70% of the energy (some might say 67%,
about 2/3rds). And 30 % resides in the charcoal.<br>
<br>
At the same time, the remaing charcoal does have about 50% of the
carbon atoms.<br>
<br>
The explaining factor is that in the carbohydrate fuels, there are
Hydrogen atoms that will all be combusted during pyrolysis, giving
the extra energy although only about 50% of the carbon atoms were
"burned".<br>
<br>
Paul<br>
<br>
<pre class="moz-signature" cols="72">Doc / Dr TLUD / Prof. Paul S. Anderson, PhD
Email: <a class="moz-txt-link-abbreviated" href="mailto:psanders@ilstu.edu">psanders@ilstu.edu</a>
Skype: paultlud Phone: +1-309-452-7072
Website: <a class="moz-txt-link-abbreviated" href="http://www.drtlud.com">www.drtlud.com</a></pre>
<div class="moz-cite-prefix">On 9/17/2017 2:36 AM, Frans Peeters
wrote:<br>
</div>
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<div class="WordSection1">
<p class="MsoNormal"><span
style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">Paul,<o:p></o:p></span></p>
<p class="MsoNormal"><span
style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D"><o:p> </o:p></span></p>
<p class="MsoNormal"><span
style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">
First cracking wood gives H20 out of its O+2H <o:p></o:p></span></p>
<p class="MsoNormal"><span
style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">Dry
wood is called 15% H2O content ……<o:p></o:p></span></p>
<p class="MsoNormal"><span
style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">Wett
wood 16-30% H2O ;needs 3 years drying .<o:p></o:p></span></p>
<p class="MsoNormal"><span
style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">Biomass
with leaves just cut 60% H20 !<o:p></o:p></span></p>
<p class="MsoNormal"><span
style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">LABO
dry means 24 h at 120 °C for 1cm thick .<o:p></o:p></span></p>
<p class="MsoNormal"><span
style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">Analytic
is for definitions . Charcoal makers may think different .<o:p></o:p></span></p>
<p class="MsoNormal"><span
style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">You
get enery from 1Kg wood= 4KWh.<o:p></o:p></span></p>
<p class="MsoNormal"><span
style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">If
you like the half now out of your wood,you can it ,during
pyrolysis .<o:p></o:p></span></p>
<p class="MsoNormal"><span
style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">You
like the other half out your charcol LATER ….You can ,and
evitting rotting !.Get easy distribution .<o:p></o:p></span></p>
<p class="MsoNormal"><span
style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">You
NEED enery to get cracking ; but that energy is not LOST
…..Use it for something the same time !<o:p></o:p></span></p>
<p class="MsoNormal"><span
style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D"><o:p> </o:p></span></p>
<p class="MsoNormal"><span
style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">Regards<o:p></o:p></span></p>
<p class="MsoNormal"><span
style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">F.<o:p></o:p></span></p>
<p class="MsoNormal"><span
style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D"><o:p> </o:p></span></p>
<p class="MsoNormal"><span
style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D"><o:p> </o:p></span></p>
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<p class="MsoNormal"><b><span
style="font-size:10.0pt;font-family:"Tahoma","sans-serif";color:windowtext"
lang="NL">Van:</span></b><span
style="font-size:10.0pt;font-family:"Tahoma","sans-serif";color:windowtext"
lang="NL"> Stoves
[<a class="moz-txt-link-freetext" href="mailto:stoves-bounces@lists.bioenergylists.org">mailto:stoves-bounces@lists.bioenergylists.org</a>] <b>Namens
</b>Paul Anderson<o:p></o:p></span></p>
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</div>
<p class="MsoNormal"><o:p> </o:p></p>
<p class="MsoNormal">To all.<br>
<br>
Thanks for the explanation of 47%C<br>
Something is still not clear:<br>
<br>
<o:p></o:p></p>
<p class="MsoNormal">Beginning with the baseline fuelwood use of
187,800 kg of fuelwood per year per village, if we assume a
10% moisture content, the baseline fuelwood is equivalent to
170,700 kg of dry fuelwood. <o:p></o:p></p>
<p class="MsoNormal">I can accept that. That is about 5 kg of
wood per household per day.<br>
<br>
<o:p></o:p></p>
<p class="MsoNormal">We assume that dry mass can be converted to
carbon mass using 47%C (Ryan et al., 2011),<o:p></o:p></p>
<p class="MsoNormal">I do not yet accept this (above). Dry
biomass is carbohydrates. C and O and H, in the approximate
proportion of CH<sub>2</sub>O (Tom Reed has more refined
proportions, but I cannot find it at this moment) . H has
almost no weight. The O (at atomic weight 16) is a bit
heavier than C at 12.. So when the O is gone during
pyrolysis, about half of the total dry weight (47%) is
attributed to carbon. That much is fine.<br>
<br>
But during pyrolysis, almost half of the carbon leaves the
scene in the form of pyrolytic combustible gases that include
C atoms. How much of the C gets converted into graphine
sheets of charcoal can vary with the pyrolysis temperature.
When pyrolysis is at less than 450 deg C, some of the carbon
still hangs around in tarry / greasy content inside of
charcoal, but it is not the same as the carbon of the
charcoal.<br>
<br>
So, if the dry wood is 170,700 kg, and half of the weight
leaves as exiting oxygen atoms, then that would be what the
article said was<br>
<br>
<o:p></o:p></p>
<p class="MsoNormal">resulting in 80,240 kgC per year per
village. <o:p></o:p></p>
<p class="MsoNormal">But that is the TOTAL of carbon. About
half of that C is gone in the pyrolytic gases, leaving about
40,100 kg C per year per village.<br>
<br>
Did I miss something? Am I talking about something
different? I am here to learn. <br>
<br>
But if I am correct, what are the implications for the Jagger
article? <br>
<br>
Paul<br>
<br>
<br>
<o:p></o:p></p>
<p class="MsoNormal"><o:p> </o:p></p>
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