[Stoves] Dehydrator

[Anderson, Paul]

Andrew,

1 kg / hr would be about the size of a regular Champion-style TLUD stove.   (I used the front side of the envelope.  Very approximate, but a good suggestion to start.)

Paul

Doc / Dr TLUD / Paul S. Anderson, PhD
Exec. Dir. of Juntos Energy Solutions NFP
Email:  psanders at ilstu.edu       Skype:   paultlud
Phone:  Office: 309-452-7072    Mobile: 309-531-4434

> -----Original Message-----
> From: Stoves <stoves-bounces at lists.bioenergylists.org> On Behalf Of Andrew
> Heggie
> Sent: Tuesday, August 14, 2018 2:54 PM
> To: Discussion of biomass cooking stoves <stoves at lists.bioenergylists.org>
> Subject: Re: [Stoves] Dehydrator
> 
> On Tue, 14 Aug 2018 at 19:13, Anderson, Paul <psanders at ilstu.edu> wrote:
> >
> > It would be nice to know how much heat energy is actually needed, but the
> real issue is to have one and put a very small diameter TLUD to give the heat.
> (maybe 4 cm = 1.5 inches).
> 
> 
> We can have a  stab at that with a back of the envelope calculation, the article
> says it dries 10kg of mangoes in 2 hours.
> 
> I'll assume mangoes are about 70% water and will need drying to 17%mc wwb,
> So it will need to remove 6.38 litres of water in 2 hours.
> Assuming again a 50% effi8ciency then  that needs about 31MJ of heat, so
> about 1kg/hour of fairly dry biomass.
> 
> Crispin has previously posted on low temperature drying/smoking of fish.
> 
> Andrew
> 
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